Plotting 3D graphs using Python and Tellurium

As an example I wanted to show how one could plot a 3D phase plot. A great example to use for this is the Lorenz Attractor. This system is interesting because it displays chaotic behavior. The differential equations for the system are given by the following three:

{\begin{aligned}{\frac {\mathrm {d} x}{\mathrm {d} t}}&=\sigma (y-x),\\{\frac {\mathrm {d} y}{\mathrm {d} t}}&=x(\rho -z)-y,\\{\frac {\mathrm {d} z}{\mathrm {d} t}}&=xy-\beta z.\end{aligned}}

Different values for the parameters, sigma, rho and beta, lead to different behaviors. The Python script below that uses Tellurium plots a 3D phase plot:

# The Lorenz Model

# The Lorenz system of equations is the classic set of
# equations which exhibit chaotic dynamics. The equations
# represent a highly simplified model of 2D thermal
# convection known as Rayleigh-Benard convection;

# The three variables, x, y and z represent the
# convective overturning, the horizontal temperature
# and vertical temperature variation respectively;

## The parameters a, b and c represent approximately
# the energy losses within the fluid due to viscosity,
# the temperature difference between the two plates
# which separate the fluid and the ratio of the vertical
# height of the fluid layer to the horizontal extent
# of the convective rolls respectively;
import tellurium as te
import roadrunner
from mpl_toolkits.mplot3d import Axes3D
import matplotlib as mpl
import matplotlib.pyplot as plt
import numpy as np

r = te.loada ('''
// Define the model in terms of three differential equations;
$s -> x; -a*(x - y);
$s -> y; -x*z + b*x - y;
$s -> z; x*y - c*z;

a = 10; b = 28; c = 2.67;
''')

# Uncomment/comment the following lines to obtain behaviour you wish to observe;

# Non-chaotic oscillations;
#r.x = 5.43027; r.y = 26.74167; r.z = 46.0098;
#r.a = 4; r.b = 91.9; r.c = 2.67;

# Single oscillation;
#r.x = 32.82341; r.y = -44.84651; r.z = 258.02389;
#r.a = 4; r.b = 191.9; r.x = 2.67;

# Stable steady-state;
#r.x = 0.1; r.y = 0.1; r.z = 0.1;
#r.a = 10; r.b = 10; r.c = 2.67;

# Chaos
r.x = 0.96259; r.y = 2.07272; r.z = 18.65888;

m = r.simulate (0, 40, 3000, ['x', 'y', 'z']);

fig = plt.figure(figsize=(8,8))
ax = fig.gca(projection='3d')

#theta = np.linspace(-4 * np.pi, 4 * np.pi, 100)
ax.plot(m[:,0], m[:,1], m[:,2], label='Lorenz Attractor')
ax.legend()

plt.show()

lorenz1

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How do I change the simulation tolerances in Tellurium?

For very complicated and large models it may be necessary to adjust the simulator tolerances in order to get the correct simulation results. Sometimes the simulator will terminate a simulation because it was unable to proceed due to numerical errors. In many cases this is due to a bad model and the user must investgate the model to determine what the issue might be. If the model is assumed to be correct then the other option is to change the simulator tolerances. The current option state of the simulator is obtained using the getInfo call, for example:

r = roadrunner.RoadRunner ('mymodel.xml')
r.getInfo()
roadrunner.RoadRunner() { 
'this' : 22F59350
'modelLoaded' : true
'modelName' : __main
'libSBMLVersion' : LibSBML Version: 5.13.0
'jacobianStepSize' : 1e-005
'conservedMoietyAnalysis' : false
'simulateOptions' : 
< roadrunner.SimulateOptions() 
{ 
'this' : 1B89AF28, 
'reset' : 0,
'structuredResult' : 0,
'copyResult' : 1,
'steps' : 50,
'start' : 0,
'duration' : 20
}, 
'integrator' : 
< roadrunner.Integrator() >
  name: cvode
  settings:
      relative_tolerance: 0.00001
      absolute_tolerance: 0.0000000001
                   stiff: true
       maximum_bdf_order: 5
     maximum_adams_order: 12
       maximum_num_steps: 20000
       maximum_time_step: 0
       minimum_time_step: 0
       initial_time_step: 0
          multiple_steps: false
      variable_step_size: false

}>

There are a variety of tuning parameters that can be changed in the simulator. Of interest are the relative and absolute tolerances, the maximium number of steps and the initial time step.

The smaller the relative tolerance the more accuate the solution, however too small a value will result in either excessive runtimes or more likely rounadoff errors. A relative tolerance of 1E-4 means that errors are controlled to 0.01%. An optimal value is roughly 1E-6. The absoute tolerance is used when a variable gets so small that the relative tolerance don’t make much sense to apply. In these situations the absolute error tolerance is used to control the error. A small value for the absolute tolerance is often desirable, such as 1E-12, we do not recommend going below 1E-15 for either tolerances.

To set the tolerances use the statements:

r.integrator.absolute_tolerance = 5e-10
r.integrator.relative_tolerance = 1e-3

Another parameter worth changing if the simulations are not working well is to change the initial time step. This is often set by the integrator to be a relatively large value which means that the integrator will try to reduce this value if there are problems. Sometimes it is better to provide a small initial step size to help the integrator get started, for example, 1E-5.

r.integrator.initial_time_step = 0.00001

The reader if refered to the CVODE documentation for more details.

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How do I plot phase plots using Tellurium?

Phase plots are a common way to visualize the dynamics of models where time courses are generated and one variable is plotted against the other. For example consider the following model that can show oscillations:

  v1: $Xo -> S1; k1*Xo;
  v2:  S1 -> S2; k2*S1*S2^h/(10 + S2^h) + k3*S1;
  v3:  S2 -> ;   k4*S2;      

In this model S2 positively activates reaction v2 thus forming a positive feedback loop. The rate equation for v2 include a Hill like coefficient term, S2^h, this determines the strength of the positive feedback. The oscillations originate from an interaction between the positive feedback and a non-obvious negative feedback loop at S1 beteen v1 and v2.

Let us assign suitable parameter values to this model, run a simulation and plot S1 versus S2.

import tellurium as te
# Import pylab to access subplot plotting feature.
import pylab as plt

r = te.loada ('''
  v1: $Xo -> S1; k1*Xo;
  v2:  S1 -> S2; k2*S1*S2^h/(10 + S2^h) + k3*S1;
  v3:  S2 -> $w; k4*S2;      

  # Initialize
  h  = 2; # Hill coefficient
  k1 = 1; k2 = 2; Xo = 1;
  k3 = 0.02; k4 = 1;
  S1 = 6; S2 = 2
''')

m = r.simulate (0, 80, 500, ['S1', 'S2'])
r.plot()

Running this script by clicking the green button in the toolbar yields the following plot:

oscillphase

What if we’d like to investigate how the oscillations are affected by the parmaeters of the model. For example how does the model bahave when we change k1? One way to do this is to plot simulations at different k1 values onto the same plot. In this case however this will create a difficult to read graph. Instead let us create a grid of subplots where each subplot represents a different simulation.

import tellurium as te
import pylab as plt

r = te.loada ('''
  v1: $Xo -> S1; k1*Xo;
  v2:  S1 -> S2; k2*S1*S2^h/(10 + S2^h) + k3*S1;
  v3:  S2 -> $w; k4*S2;      

  # Initialize
  h  = 2; # Hill coefficient
  k1 = 1; k2 = 2; Xo = 1;
  k3 = 0.02; k4 = 1;
  S1 = 6; S2 = 2
''')

plt.subplots(3,3)
plt.figure(figsize=(12,6)) 
for i in range (9):
    r.reset()
    m = r.simulate (0, 80, 500, ['S1', 'S2'])
    plt.subplot (3,3,i+1)
    plt.plot (m[:,0], m[:,1], "k1=" + str (r.k1))
    plt.legend()
    r.k1 = r.k1 + 0.2

Here we create a 3 by 3 subplot grid, start a loop that changes k1 and each time round the loop it plots the simulation onto one of the subplots. Running this script results in the following output

oscillphasegrid

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How to get the Stoichiometry Matrix using Tellurium

Here is a simple need, given a reaction model how do we get hold of the stoichiometry matrix?

Consider the following simple model:

import tellurium as te
import roadrunner

r = te.loada("""
     $Xo -> S1; k1*Xo;
      S1 -> S2; k2*S1;
      S2 -> S3; k3*S2;
      S3 -> $X1; k4*S3;
      
      k1 = 0.1; k2 = 0.4;
      k3 = 0.5; k4 = 0.6;
      Xo = 1;
""")

print r.getFullStoichiometryMatrix()

Running this script by clicking on the green arrow in the tool bar will yield:

      _J0, _J1, _J2, _J3
S1 [[   1,  -1,   0,   0],
S2  [   0,   1,  -1,   0],
S3  [   0,   0,   1,  -1]]

The nice thing about this output is that the columns and rows are labeled so you know exact what is what.

What about much larger models? For example the iAF1260.xml model from the Bigg database (http://bigg.ucsd.edu:8888/models/iAF1260). This is a model of E. Coli that includes 1668 metabolites and 2382 reactions. We can download the iAF1260.xml file and load it into libRoadRunner using:

 
r = roadrunner.RoadRunner ('iAF1260.xml')

This might take up to a minute to load depending on how fast your computer is. We are assuming here that the file is located in the current directory (os.getcwd()). If not, move the file, change the current directory (using os.chdir), or use the appropriate path in the call.

Rather than print out the stoichiometry matrix (don’t even try) to the screen we’ll save it to a file. Because the stoichiometry matrix is so large we will use numpy to write the matrix out as a text file:

import numpy as np
r = roadrunner.RoadRunner ('iAF1260.xml')
st = r.getFullStoichiometryMatrix()
print "Number of metabolites = ", r.getNumFloatingSpecies()
print "Number of reactions = ", r.getNumReactions()
np.savetxt ('stoich.txt', st)

Number of metabolites = 1668
Number of reactions = 2382

One can change the formating of the output using savetxt, for example the following will output the individual stoichiometry coefficeint using 3 decimal places, 5 characters minimium, and separated by a comma.

np.savetxt ('c:\\tmp\\st.txt', st, delimiter=',', fmt='%5.3f',)

You can get the labels for the rows and columns by calling r.getFloatingSpeciesIds() and r.getReactionIds() respectively.

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How to do a simple simulation using Telluirum

The most common requirement is the ability to carry out a simple time course simulation of a model. Consider the model:

    \[S_1 \rightarrow S_2 \rightarrow S_2\]

Two reactions and three metabolites, S1, S2 and S3. We can describe this system using an Antimony string:

import tellurium as te
import roadrunner

r = te.loada ('''
   S1 -> S2; k1*S1;
   S2 -> S3; k2*S2;

   k1= 0.4; k2 = 0.45
   S1 = 5; S2 = 0; S3 = 0 
''')

m = r.simulate (0, 20, 100)
r.plot()

Run the script by clicking on the green arrow in the tool bar to yield:

simpletimecourse

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How do I run a stochastic simulation using Tellurium/libRoadRunner?

In this post I will show you how to run a stochastic simulation using our Tellurium application. Tellurium is a set of libraries that can be used via Python. One of those libraries is libRoadRunner which is our very fast simulator. It can simulate both stochastic and detemrinistic models. Let’s illustrate a stochastic simulation using the following simple model:

import tellurium as te
import numpy as np

r = te.loada('''
    J1: S1 -> S2;  k1*S1;
    J2: S2 -> S3;  k2*S2
    J3: S3 -> S4;  k3*S3;

    k1 = 0.1; k2 = 0.5; k3 = 0.5;
    S1 = 100;
''')

We’ve set up the number of initial molecules of S1 to be 100 molecules. The easiest way to run a stochastic simulation is to call the gillespie method on roadrunner. This is shown in the code below:

m = r.gillespie (0, 40, steps=100)
r.plot()

Running this by clicking on the green button in the tool bar will give you the plot:

gill1

What if you wanted to run a lot of gillespie simulations to get an idea of the distribution of trajectories? TO do that just just need ot repeat the simulation many times and plot all the results on the same graph:

import tellurium as te
import numpy as np

r = te.loada('''
    J1: S1 -> S2; k1*S1;
    J2: S2 -> S3; k2*S2
    J3: S3 -> S4; k3*S3;

    k1 = 0.1; k2 = 0.5; k3 = 0.5;
    S1 = 100;
''')

# run repeated simulation
numSimulations = 50
points = 101
for k in range(numSimulations ):
    r.resetToOrigin()
    s = r.gillespie(0, 50)
    # No legend, do not show
    r.plot(s, show=False, loc=None, alpha=0.4, linewidth=1.0)

This script will yield the plot:

tmp

We can do one other thing and compute the average trajectory and overlay the plot with the average line. The one thing we have to watch out for is that we must set the integrator property variable_step_size = False to false. This will ensure that time points are equally spaced and that all trajectories end at the same point in time.

import tellurium as te
import numpy as np

r = te.loada('''
    J1: S1 -> S2; k1*S1;
    J2: S2 -> S3; k2*S2
    J3: S3 -> S4; k3*S3;

    k1 = 0.1; k2 = 0.5; k3 = 0.5;
    S1 = 100;
''')

# run repeated simulation
numSimulations = 50
#points = 101
# Set the physical size of the plot (units are in inches)
plt.figure(figsize=(10,5))
r.setIntegrator ('gillespie')
# Make sure we do this so that all trajectories 
# are the same length and spacings
r.getIntegrator().variable_step_size = False
s_sum = np.array(0.)
for k in range(numSimulations):
    r.resetToOrigin()
    s = r.simulate(0, 100, steps=50)
    s_sum = np.add (s_sum, s)
    # no legend, do not show
    r.plot(s, show=False, loc=None, alpha=0.4, linewidth=1.0)

# add mean curve, legend, show everything and set labels, titels, ...
s_mean = s_sum/numSimulations
r.plot(s_mean, loc='upper right', show=True, linewidth=3.0,
       title="Stochastic simulation", xlabel="time", 
       ylabel="concentration", grid=True); 

This will give us the following plot:

tmp

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Computing the steady state using Tellurium

If you’re building a model and you want to quickly find the model’s steady state, you can call the command steadyState. Let’s illustrate this with an example:

import tellurium as te

r = te.loada ('''
     # Define a simple linear chain of reactions
     $Xo -> S1; k1*Xo;
      S1 -> S2; k2*S1;
      S2 -> S3; k3*S2;
      S3 -> $X1; k4*S3;

  # Initialize rate constants 
  k1 = 0.2; k2 = 0.7; k3 = 0.15; k4 = 1.3;
  Xo = 10
''')

print r.getSteadyStateValues() 

Running this script by clicking in the green arrow in the tool bar will output the following steady state levels:

[2.85714286  13.33333333   1.53846154]

But which steady state value refers to which species in my model? To find that out call getFloatingSpeciesIds:

print r.getFloatingSpeciesIds()
['S1', 'S2', 'S3']

The order of the speces Ids match the order of steady state values. In other words, S1 = 2.857, S2 = 13.333, and S3 = 1.538.

If you want to check that these values really are the steady state values you can compute the rates of change:

print r.getRatesOfChange()
array([  0.00000000e+00,  -4.44089210e-16,   4.44089210e-16])

If you look carefully all the rates of change are effectively zero, thus confirming we’re at steady state.

What about the stability of the steady state? That is, is it stable to small perturbations in S1, S2 or S3? To find this out we need to compute the eigenvalues of the system Jacobian matrix. If all the eigenvalues are negative this means small pertubrations are damped so that the system returns to the steady state. There are two ways to do this, we can use the getReducedEigenValues call, or we get compute the Jacobian first and then compute the eigenvalues of the Jacobian. Both these approaches are given below. Its probably simplest to call just getReducedEigenValues.

print r.getReducedEigenValues()
[-0.7  -0.15 -1.3 ]

Notice that all the eigenvalues are negative indicating that small perturbations are stable.

This is the alternative approach which computes the Jacobian first and then the eigenvalues of the Jacobian:

print te.getEigenvalues(r.getFullJacobian())
[-0.7  -0.15 -1.3 ]

Note that we’re using a utility method from the tellurium library, getEigenValues to compute the eigenvalues.

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Bifurcation Analysis with Tellurium

bifirreversible
I thought I’d try and write a series of HowTos on Tellurium, our python based tool for the construction, simulation and analysis of biochemical models. Details on this tool can be found here.

One the unique features of Tellurium is that it comes with the AUTO2000 package. This is a well established software library for performing a bifurcation analysis.

Unlike other implementations (not includng oscill8), AUTO2000 in Telluirum does not require a separate compiler to compile the model for AUTO2000 to compute the differential equations. This makes it easier to delpoy and users don’t have to worry about such details. AUTO2000 uses libRoadRunner to access and compute the model.

Let’s begin with an example from my text book “Systems Biology: Introduction to Pathway Modeling”, Figure 12.20, page 279 in revision 1.1 of the book. The model in question is a modified model from the ‘Mutual activation’ model in the review byTyson (Current Opinion in Cell Biology 15:221–231, Figure 1e). In this example increasing the signal results in the system switching to the high state at around 2.0. If we reduce the signal from a high level, we traverse a different steady state. If we assume the signal can never be negative, we will remain at the high steady state even if the signal is reduced to zero. The bifurcation plot in the negative quadrant of the graph is physically inaccessible. This means it is not possible to transition to the low steady state by decreasing signal. As a result, the bistable system is irreversible, that is, once it is switched on, it will always remain on. To compute the bifurcation diagram we first define the model:

import tellurium as te
import teplugins
import pylab as plt

r = te.loada ('''
    $X -> R1;  k1*EP + k2*Signal;
    R1 -> $w;  k3*R1;
    EP -> E;   Vm1*EP/(Km + EP);
    E -> EP;   ((Vm2+R1)*E)/(Km + E);
    Vm1 = 12; Vm2 = 6;
    Km = 0.6;
    k1 = 1.6; k2 = 4;
    E = 5; EP = 15;
    k3 = 3; Signal = 0.1;
''')

We’ve imported three packages, tellurium to load the model, teplugins to access AUTO2000 and pylab to gain acess to matplotlib. Once we have the model loaded we can get a handle on AUTO2000 by calling teplugins.Plugin(“tel_auto2000”) and set a number of properties in AUTO2000. This includes loading the model into AUTO200, identifying the parameter we wish to modify for the bifurcation diagram (in this case signal), following by some options to carry out a pre simulation to help with the initial location of the steady state and finally the limits for x axis for the plot, in this case -2 to 3. Details of other propoerties to change can be found by typing auto.viewManual(), make sure you have a pdf reader available. The alternative is to go to the intro page.

auto = teplugins.Plugin("tel_auto2000")

auto.setProperty("SBML", r.getCurrentSBML())
auto.setProperty("ScanDirection", "Negative")
auto.setProperty("PrincipalContinuationParameter", "Signal")
auto.setProperty("PreSimulation", "True")
auto.setProperty("PreSimulationDuration", 1.0)
auto.setProperty("RL0", -2.0)
auto.setProperty("RL1", 3.0)

To run the bifurcation analysis we use the Python code:

auto.execute()

If all was successful we can next plot the results. It is possible to plot the results using your own code (see below) but it might be more convenient to use the builtin facilties, for example:

pts     = auto.BifurcationPoints
lbls    = auto.BifurcationLabels
biData  = auto.BifurcationData
biData.plotBifurcationDiagram(pts, lbls)

The pts vector contains the point coordinates where the bifurcation points are located. lbls give the labels that correspond to the pts vector and indicate what type of bifurcation point it represented. Finally a special object, here called biData contains the data together with a number of useful utilties. The import important of these is biData.plotBifurcationDiagram(pts, lbls) which takes pts and lbls as arguments. Running this code will generate the bifurcation plot shown belowbifirreversible.

We can also print out a text summary of the computation using the command, auto.BifurcationSummary, which returns a summary of tjhe fidnnngs.

Summary :
BR PT TY LAB PAR(0) L2-NORM U(1) U(2)
1 1 EP 1 3.00000E+000 2.38908E+001 1.42336E+001 1.91879E+001
1 50 2 5.48632E-001 2.14502E+001 1.06592E+001 1.86144E+001
1 95 LP 3 -9.31897E-001 1.79088E+001 7.44448E+000 1.62881E+001
1 100 4 -9.13592E-001 1.74094E+001 7.22867E+000 1.58377E+001
1 150 5 1.74114E-001 1.26908E+001 6.15211E+000 1.10999E+001
1 200 6 1.54579E+000 8.36095E+000 5.44499E+000 6.34488E+000
1 234 LP 7 2.06965E+000 5.51178E+000 4.47540E+000 3.21723E+000
1 250 8 1.84381E+000 4.03137E+000 3.51306E+000 1.97747E+000
1 300 9 -5.77433E-001 7.02653E-001 -5.14930E-001 4.78089E-001
1 325 EP 10 -2.00625E+000 2.56175E+000 -2.55121E+000 2.32100E-001

We can manually plot the data by gaining access to the numpy version of the data. To do this we use:

pltData = biData.toNumpy

pltData is a numpy array where the first column is the bifurcation parameter and the remaning columns contain the species. For example to plot the bifurcation diagram for the first species in the model, R1 we would use:

plt.plot(x[:,0], x[:,1], linewidth=2)
plt.axvline(0, color='black')
plt.xlabel ("Signal")
plt.ylabel ("R1")

I added a axvline command to draw a vertical line from the zero axis. I also added some axis labeling statements. These commands will result in:
bifirreversible2

What is interesting about this model is that the upper branch reaches the zero parameter value before the turning point. This means it is difficult to switch to the lower steady state by just lowering the signal.

Viewing thee Network

One other things we can do is view the model as a network. Telluirum comes witha simple network viewer in the package nwed. import the viewer using

import nwed

at the ipython console. To view the network make sure the network viewer panel is visible, do this by going to the View menu, find panes and select, then look down the menu items and near the bottom you’ll find Network Viewer, select this option. To view the network, type the following at trhe ipython console.

nwed.setsbml (r.getSBML())

The viewer should now display something like:

nwedlayout

Note that every view will be different and depends on the layout algorithm.

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Tikz Code for Drawing Metabolic Feedback Loops

I needed some figures that displayed a variety of different negative feedback loops so I created these using Tikz. Nothing particularly special. There are some absolute distances in the code which perhaps could be removed to make it more generic.

feedbackdiagrams

 

\documentclass{article}

\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{arrows}
\usetikzlibrary{calc}

\begin{document}

\begin{tikzpicture}[>=latex', node distance=2cm]
\node (Xo) {};
\node [right of = Xo] (S1) {\Large $x$};
\node [right of = S1] (S2) {};

\draw [->,ultra thick,blue] (Xo) -- node[above, black] {$v_1$} (S1);
\draw [->,ultra thick,blue] (S1) -- node[above, black] {$v_2$} (S2);

% Lets draw a line with a blunt end, -|
\draw [-|,ultra thick,blue]
% start in the middle of S2, and move down 2.75 mm
% ($ ... $) notation is used to add the coordinates
($ (S1) + (0mm,-2.75mm) $)

% Now draw the line down by 3mm
% -- means draw to, + means move by
-- +(0,-3mm)
% Now move back to the left of S2
% The symbol -| means draw horizontal then vertical.
% If we used -- instead the line would be drawn
% diagonally to the reaction edge.
% (S1) is the center of the node. But we want the
% blunt end to end below the S1 line and
% half way to the left. The 10mm is half the node
% distance of 2cm, and 1mm is slightly below
% the reaction line.
-| ($ (S1) - (10mm,1mm) $);
\end{tikzpicture}

\vspace{1cm}

\begin{tikzpicture}[>=latex', node distance=2cm]
\node (Xo) {};
\node [right of = Xo] (x1) {\Large $x_1$};
\node [right of = x1] (x2) {\Large $x_2$};
\node [right of = x2] (x3) {};

\draw [->,ultra thick,blue] (Xo) -- node[above, black] {$v_1$} (x1);
\draw [->,ultra thick,blue] (x1) -- node[above, black] {$v_2$} (x2);
\draw [->,ultra thick,blue] (x2) -- node[above, black] {$v_3$} (x3);

% Lets draw a line with a blunt end, -|, using the following coords
\draw [-|,ultra thick,blue]
% start in the middle of x2, and move down 2.75 mm
% ($ ... $) notation is used to add the coordinates
($ (x2) + (0mm,-2.75mm) $)

% Now draw the line down by an additional 3mm
% -- means draw to, + means move by
-- +(0,-3mm)

% Now move back to the left of x2
% The symbol -| means draw horizontal then vertical.
% If we used -- instead the line would be drawn
% diagonally to the reaction edge.
% (S1) is the center of the node. But we want the
% blunt end to end below the S1 line and
% half way to the left. The 10mm is half the node
% distance of 2cm, and 1mm is slightly below
% the reaction line.
-| ($ (x1) - (10mm,1mm) $);
\end{tikzpicture}

\vspace{1cm}

\begin{tikzpicture}[>=latex', node distance=2cm]
\node (Xo) {};
\node [right of = Xo] (x1) {\Large $x_1$};
\node [right of = x1] (x2) {\Large $x_2$};
\node [right of = x2] (x3) {\Large $x_3$};
\node [right of = x3] (x4) {};

\draw [->,ultra thick,blue] (Xo) -- node[above, black] {$v_1$} (x1);
\draw [->,ultra thick,blue] (x1) -- node[above, black] {$v_2$} (x2);
\draw [->,ultra thick,blue] (x2) -- node[above, black] {$v_3$} (x3);
\draw [->,ultra thick,blue] (x3) -- node[above, black] {$v_4$} (x4);

% Lets draw a line with a blunt end, -|
\draw [-|,ultra thick,blue]
($ (x3) + (0mm,-2.75mm) $)
-- +(0,-3mm)
-| ($ (x1) - (10mm,1mm) $);
\end{tikzpicture}

\vspace{1cm}

\begin{tikzpicture}[>=latex', node distance=2cm]
\node (Xo) {};
\node [right of = Xo] (x1) {\Large $x_1$};
\node [right of = x1] (x2) {\Large $x_2$};
\node [right of = x2] (x3) {\Large $x_3$};
\node [right of = x3] (x4) {\Large $x_4$};
\node [right of = x4] (x5) {};

\draw [->,ultra thick,blue] (Xo) -- node[above, black] {$v_1$} (x1);
\draw [->,ultra thick,blue] (x1) -- node[above, black] {$v_2$} (x2);
\draw [->,ultra thick,blue] (x2) -- node[above, black] {$v_3$} (x3);
\draw [->,ultra thick,blue] (x3) -- node[above, black] {$v_4$} (x4);
\draw [->,ultra thick,blue] (x4) -- node[above, black] {$v_5$} (x5);

% Lets draw a line with a blunt end, -|
\draw [-|,ultra thick,blue]
($ (x4) + (0mm,-2.75mm) $)
-- +(0,-3mm)
-| ($ (x1) - (10mm,1mm) $);
\end{tikzpicture}

\vspace{1cm}

\begin{tikzpicture}[>=latex', node distance=2cm]
\node (Xo) {};
\node [right of = Xo] (x1) {\Large $x_1$};
\node [right of = x1] (x2) {\Large $x_2$};
\node [right of = x2] (x3) {\Large $x_3$};
\node [right of = x3] (x4) {};

\draw [->,ultra thick,blue] (Xo) -- node[above, black] {$v_1$} (x1);
\draw [->,ultra thick,blue] (x1) -- node[above, black] {$v_2$} (x2);
\draw [->,ultra thick,blue] (x2) -- node[above, black] {$v_3$} (x3);
\draw [->,ultra thick,blue] (x3) -- node[above, black] {$v_4$} (x4);

% Lets draw a line with a blunt end, -|
\draw [-|,ultra thick,blue] (10mm, -8mm)
-- +(0,6mm);
\node (x) at (10mm,-11mm) {\Large $x$};
\end{tikzpicture}

\end{document} 
Posted in LaTeX, Modeling, Pathways, Programming, Publishing | Leave a comment

The Confusion of Modern Textbooks – Stylistic Sugar

I’ve been looking for a textbook on statistics for a class I’ll teach in the autumn term. While the content of many textbooks might be ok the way the information is presented makes them difficult to read – at least it does for me. This applies to most undergraduate textbooks published today whether they be about statistics or other topics. There seems to be a need by publishers to embellish textbooks with so much stylistic sugar that the content is buried.

I scanned two typical pages from a second-hand stats textbook I bought from Goodwill to illustrate what I mean.

Pages54And55

I’ve marked using a red star the many different styles used in the text book on two random pages, these include:

1. Section heading with a vertical dark purple line
2. Highlighted area using three colors (black, blue and purple)
3. A notes section with blue heading
4. An Illustration section using blue font but spaced out letters and thin left-bar in dark purple
4. Up and down purple arrows in illustration section indicating question and answer
6. Paragraph of text using back font (finally something normal)
7. Figure caption in dark purple text with green vertical line and horizonal line in black
8. Exercise box in margin with heading in white with black background
9. Exercise box where the question in black with yellow background
10. Typewriter font for computer code with black and blue horizontal lines delimiting code

Not included in these pages are also other stylistic sugar:

1. Case study section that uses five colors and six stylistic features
2. Exercises with six stylistic features including at least eleven different symbols
3. Call-out in exercises using a script font with blue background.
3. Chapter practice tests in black font with blue background and thick blue horizontal line
4. Chapter Objective in black font, red bullet point in off yellow background with vertical dotted line.
5. Chapter heading page, eight stylistic features with multiple fonts

And this is before a student has even started to read the content I counted at least 15 different fonts used in the text.

 

Posted in General Interest, Publishing, Textbooks | Leave a comment